Transform an exponential variable

Problem

Let X∼Exponential⁡(2)X\sim\operatorname{Exponential}(2) under the rate parameterization and define Y=2XY=2X. Derive the CDF and PDF of YY, identify its distribution, and give its mean and variance.

Reveal answer or reference solution

For y<0y<0, FY(y)=0F_Y(y)=0. For y≥0y\ge0,

FY(y)=P(2X≤y)=P(X≤y/2)=1−e−2(y/2)=1−e−yF_Y(y)=P(2X\le y)=P(X\le y/2)=1-e^{-2(y/2)}=1-e^{-y}

Differentiating gives fY(y)=e−yf_Y(y)=e^{-y} for y≥0y\ge0 and 00 otherwise. Hence Y∼Exponential⁡(1)Y\sim\operatorname{Exponential}(1). Its mean is 11 and its variance is 11.

Outcome

Previous attempts

Loading attempts saved in this browser…

    Review Screening Results